2n^2-15n-8=0

Solution for 2n^2-15n-8=0 equation:

2n^2-15n-8=0

a = 2; b = -15; c = -8;
Δ = b2-4ac
Δ = -152-4·2·(-8)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-17}{2*2}=\frac{-2}{4}
=-1/2
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+17}{2*2}=\frac{32}{4}
=8
$